Question

solve it...........​

Answer 1

❤pyalli pgl ❤

bita = lemda × D /d

∆ bita = lemda ∆D/d

lemda = ∆B ×d/ ∆D

lemda = (10^-3)(0.03×10^-3)/5×10^-2

= 5000A°

Answer 2

Answer:

Given:

Distance between screen and slit = D = 5 × 10^-2 m

fringe width = X = 10^-2 m

distance between slits = d = 0.3 mm = 0.3 × 10^-3 m

Wavelength = ?

We have,

wavelength of light = Xd/D

= 10^-2 × 0.3 × 10^-3 / 5 × 10^-2

= 0.06 × 10^-3

= 600000 × 10^-10 m

= 600000 A°

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I think , fringe width should be 0.03 mm

and distance between slits should be 10^-3 m.

So, as to give wavelength 6000 A°