Question

Solve it................​

Answer 1

Answer:

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Plz... Follow mE_____✌️✌️✌️

Answer 2

Answer:

3

Step-by-step explanation:

let

y =

$\sqrt{6 + \sqrt{6 + \sqrt{6+ \sqrt{6+ ...} } } }$

on squaring both side

y^2 =

$6 + \sqrt{6 + \sqrt{6 + \sqrt{6 + \sqrt{6...} } } }$

so

y^2 - y - 6 = 0

y^2 -3y + 2y - 6 = 0

(y - 3)(y +2) = 0

so

y = 3