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☆Hey Mate!!!☆
As we know that,
![area \: of \: trapezium = \frac{1}{2} \times h( \: sum \: of \: parallel \: sides \: ) \\100 {cm}^{2} = \frac{1}{2} \times h(12 + 8)cm \\ 100 {cm}^{2} \times 2 \times \frac{1}{20cm} = h \\ 10cm = height area \: of \: trapezium = \frac{1}{2} \times h( \: sum \: of \: parallel \: sides \: ) \\100 {cm}^{2} = \frac{1}{2} \times h(12 + 8)cm \\ 100 {cm}^{2} \times 2 \times \frac{1}{20cm} = h \\ 10cm = height](https://tex.z-dn.net/?f=area+%5C%3A+of+%5C%3A+trapezium+%3D++%5Cfrac%7B1%7D%7B2%7D++%5Ctimes+h%28+%5C%3A+sum+%5C%3A+of+%5C%3A+parallel+%5C%3A+sides+%5C%3A+%29+%5C%5C100++%7Bcm%7D%5E%7B2%7D++%3D++%5Cfrac%7B1%7D%7B2%7D++%5Ctimes+h%2812+%2B+8%29cm+%5C%5C+100+%7Bcm%7D%5E%7B2%7D++%5Ctimes+2+%5Ctimes++%5Cfrac%7B1%7D%7B20cm%7D++%3D+h+%5C%5C+10cm+%3D+height)
Hope it helps☺!
As we know that,
Hope it helps☺!
nitthesh7:
was my ans down looks of content quality ???
Answered by
2
Area of Trapezium = (a+b)h/2
And Here a and b are parallel sides,
So, a = 12 cm
b = 8 cm
Area = 100 cm²
Distance Between the parallel sides = h
Then in formula,
Area of Trapezium = (a+b)h/2
100 = (12+8)h/2
2 × 100 = 20h
h = 200/20
h = 10 cm
Hence Distance between parallel sides is 10 cm.
And Here a and b are parallel sides,
So, a = 12 cm
b = 8 cm
Area = 100 cm²
Distance Between the parallel sides = h
Then in formula,
Area of Trapezium = (a+b)h/2
100 = (12+8)h/2
2 × 100 = 20h
h = 200/20
h = 10 cm
Hence Distance between parallel sides is 10 cm.
☺ Hope this Helps ☺
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