Math, asked by perticasinghsoni, 1 year ago

SolVE IT.... ............

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Answered by ShuchiRecites
2
☆Hey Mate!!!☆

As we know that,

area \: of \: trapezium =  \frac{1}{2}  \times h( \: sum \: of \: parallel \: sides \: ) \\100  {cm}^{2}  =  \frac{1}{2}  \times h(12 + 8)cm \\ 100 {cm}^{2}  \times 2 \times  \frac{1}{20cm}  = h \\ 10cm = height

Hope it helps☺!

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Answered by nitthesh7
2
Area of Trapezium =  (a+b)h/2

And Here a and b are parallel sides,

So,    a = 12 cm

          b = 8 cm

     Area = 100 cm²

Distance Between the parallel sides = h


Then in formula,
 
 Area of Trapezium  =  (a+b)h/2

                          100 =  (12+8)h/2

                    2 × 100 = 20h

                              h = 200/20

                              h = 10 cm

Hence Distance between parallel sides is 10 cm.


☺ Hope this Helps 



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