solve it.................
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3^(2x-8)/225=5^3/5^x
we can write the above eq as
3^(2x-8)/3^2×5^2=5^(3-x)
3^(2x-8-2)=5^(3-x+2)
3^(2x-10)=5^(5-x)
3^(-2)(5-x)=5^(5-x)
[3^(-2)/5]^(5-x)=1
so 5-x=0
=> x=5.
hope it will help you.
we can write the above eq as
3^(2x-8)/3^2×5^2=5^(3-x)
3^(2x-8-2)=5^(3-x+2)
3^(2x-10)=5^(5-x)
3^(-2)(5-x)=5^(5-x)
[3^(-2)/5]^(5-x)=1
so 5-x=0
=> x=5.
hope it will help you.
Aakriti001:
plz mark it as brainlest..if u find it useful.
Answered by
1
Hope it will help u.... plz mark as brainliest
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