solve it.................
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3^(2x-8)/225=5^3/5^x
we can write the above eq as
3^(2x-8)/3^2×5^2=5^(3-x)
3^(2x-8-2)=5^(3-x+2)
3^(2x-10)=5^(5-x)
3^(-2)(5-x)=5^(5-x)
[3^(-2)/5]^(5-x)=1
so 5-x=0
=> x=5.
hope it will help you.
we can write the above eq as
3^(2x-8)/3^2×5^2=5^(3-x)
3^(2x-8-2)=5^(3-x+2)
3^(2x-10)=5^(5-x)
3^(-2)(5-x)=5^(5-x)
[3^(-2)/5]^(5-x)=1
so 5-x=0
=> x=5.
hope it will help you.
Aakriti001:
plz mark it as brainlest..if u find it useful.
but how i'm a new comer i don't know all the functions of it
ohkk...nice to help you
thanks
Answered by
1
Hope it will help u.... plz mark as brainliest
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Thanks a lot
thanks for mark
Hmne acceleration wale ka bhi ans dia h
ok but i had solved it
i can't understand last 2nd line
of it..
neha solve the last one which i had posted recently.
okkkk
thanks
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