solve it.........6...
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Let 100x + 10y + z be the 3 digit number.
y = 3z
x = 4z
x + y + z = 16
4z + 3z + z = 16
8z = 16
z = 2
x = 8
y = 6
The number is 862
y = 3z
x = 4z
x + y + z = 16
4z + 3z + z = 16
8z = 16
z = 2
x = 8
y = 6
The number is 862
Answered by
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Let the units digit be x
Then, tens digit = 3x
and hundreds digit = 4x
Then the number is (100 × 4x) + (10×3x) + (x)
Sum of digits = x + 3x + 4x
=> 16 = 8x
=> x = 16 / 8
=>x = 2
So, the number is (100× 4 (2) ) + (10× 3 (2) ) + (2) =800 + 60 + 2 = 862
Then, tens digit = 3x
and hundreds digit = 4x
Then the number is (100 × 4x) + (10×3x) + (x)
Sum of digits = x + 3x + 4x
=> 16 = 8x
=> x = 16 / 8
=>x = 2
So, the number is (100× 4 (2) ) + (10× 3 (2) ) + (2) =800 + 60 + 2 = 862
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