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sum of n terms of AP is (n/2){2a+(n-1)d}
a/q
11/2{2a+10d} = 19/2{2a+18d}
=>22(a+5d)=38(a+9d)
=>-16a=232d
=>-2a=29d
now sum of 30 terms is 30/2{2a+29d)=0
a/q
11/2{2a+10d} = 19/2{2a+18d}
=>22(a+5d)=38(a+9d)
=>-16a=232d
=>-2a=29d
now sum of 30 terms is 30/2{2a+29d)=0
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