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An object is in the shape of a right circular cylinder with a hemisphere on one end and a cone on the other. The height and radius of the cylindrical part are 13 cm and 5 cm respectively. The radii of the hemispherical and conical parts are the same as that of the cylindrical part. Calculate the surface area of the object if the height of the conical part is 12 cm.
Answers
Answer:
A similar one
Step-by-step explanation:
Total height= 30cm
height of cylinder=13cm
height of cone=30-18 (radius of hemisphere=height)
therefore height of cone= 12cm
C.S.A. of hemisphere:
2*22/7*5^2
=157.14 cm^2
C.S.A. of cylinder:
2*22/7*5*13
=408.571 cm^2
C.S.A of cone :
22/7*5*13
=204.28
Adding all C.S.As we get
408.57
204.28
+157.14
=769.99m^2 [Ans. =Surface area of toy]
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Answer:
Heya !!
Here's your answer..
___________________
Radius of cylinder = Radius of cone = Radius of hemi sphere = 5cm
Height of cylinder ( h1 ) = 13cm
Height of cone ( h2 ) = 12cm
Slant height of cone ( l )² = r² + h2²
l² = 5² + 12²
l² = 25 + 144
l = √169
l = 13cm
Surface area of figure = C.S.A of cone + C.S.A of cylinder + C.S.A of H.S
= πrl + 2πrh1 + 2πr²
= πr ( l + 2h1 + 2r )
= 22/7 × 5 [ 13 + 2(13) + 2(5) ]
= 22/7 × 5 [ 13 + 26 + 10 ]
= 22/7 × 5 [ 49 ]
= 22 × 5 × 7
= 110 × 7
= 770cm square.