Question

Solve it by

Completing square method

Class 10

Answer 1

Step-by-step explanation:

$x ^{2} - 4 \sqrt{2} x + 6 = 0 \\ x ^{2} - 3 \sqrt{2} x - \sqrt{2}x + 6 = 0 \\ x(x - 3 \sqrt{2} ) \: - \: \sqrt{2} (x - 3 \sqrt{2} ) \\ (x - 3 \sqrt{2} )(x - \sqrt{2} ). \\ 2. \: 2x ^{2} - 7x + 3 \\ 2x ^{2} - 6x - x + 3 \\ 2x(x + 3) - 1(x + 3) \\ (x + 3)(2x - 1).$