Question

solve it by factorization method
5(3x+1) ^2+6(3x+1) -8=0​

Answer 1

Answer:

If $5(3x+1) ^2+6(3x+1) -8=0$ then $15x^2 + 16x + 1=0$

Step-by-step explanation:

Formula: $(a + b)^2 = a^2 + 2ab + b^2$

$5(3x+1) ^2+6(3x+1) -8=0\\5[(3x)^2 + 2 \times 3x \times 1 + 1] + 6 (3x) + 6(1) - 8 =0\\5(9x^2 + 6x + 1)+ 18x + 6 - 8=0\\45x^2 + 30x + 5 + 18x - 2 =0$

Rearrange the similar terms

$45x^2 + 30x + 18x + 5 - 2 =0\\45x^2 + (30 +18)x + 3=0\\45x^2 + 48x + 3 = 0\\3(15x^2 + 16x + 1) =0\\15x^2 + 16x + 1 = 0$