SOLVE IT BY SIMULTANEOUS EQUATION
3 men and 4 boys can do a piece of work in 14 days while 4 men and 6 boys can do it in 10 days. How long would it take 1 boy to finish the work
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Answer:
let 1mans 1 days work = x
n 1boys 1 days work = y
so
3x + 4y = 1/14
4x + 6y = 1/10
after solving simultaneously, we get
x= 1/70 ,y= 1/140
so 1 boy would need 140 days to complete the work.
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