Question

.solve it by substitution method..... ​

Answer 1

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Keep only one variable in LHS

√2x+√3y=0

√2x=-√3y

x=-√3y/√2 ... equation 1

√3x+√8y=0 ... equation 2

Substitute eq.1 in eq.2

√3x+√8y=0

√3(-√3y/√2)+√8y=0

-3y/√2+(√8y)√2/√2=0

-3y/√2+√16y/√2=0

-3y/√2+4y/√2=0

-3y+4y/√2=0

y/√2=0

y=0

Substitute y=0 in equation 1

x=-√3y/√2

x=(-√3)0/√2

x=0/√2

x=0

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Answer 2

Answer:

Step-by-step explanation:

sorry for bad handwriting i did it on pc with mouse