Question

Solve it by the process of factorisation
$4x {}^{2} + 1$please don't make it an equation

Answer 1

$4 {x}^{2} + 1 = 4 {x}^{2} + 4xy + 1 - 4xy \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = {(2x + 1)}^{2} - 4xy \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = (2x + 1)(2x + 1) - 4xy$

Answer 2

Please see the attachment