solve it by using elimination method :- 0.4x + 0.3y = 1.7,
0.7x - 0.2 y = 0.8
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Answered by
10
Given 0.4x + 0.3y = 1.7 -------- (1)
Given 0.7x - 0.2y = 0.8 -------- (2)
On solving (1) * 0.7 & (2) * 0.4, we get
0.28x + 0.21y = 1.19
0.28x - 0.08y = 0.32
---------------------
0.29y = 0.87
y = 0.87/0.29
y = 3.
Substitute y = 3 in (1), we get
0.4x + 0.3y = 1.7
0.4x + 0.3(3) = 1.7
0.4x + 0.9 = 1.7
0.4x = 1.7 - 0.9
0.4x = 0.8
x = 0.8/0.4
x = 2.
Therefore the value of x = 2 and y = 3.
Hope this helps!
Given 0.7x - 0.2y = 0.8 -------- (2)
On solving (1) * 0.7 & (2) * 0.4, we get
0.28x + 0.21y = 1.19
0.28x - 0.08y = 0.32
---------------------
0.29y = 0.87
y = 0.87/0.29
y = 3.
Substitute y = 3 in (1), we get
0.4x + 0.3y = 1.7
0.4x + 0.3(3) = 1.7
0.4x + 0.9 = 1.7
0.4x = 1.7 - 0.9
0.4x = 0.8
x = 0.8/0.4
x = 2.
Therefore the value of x = 2 and y = 3.
Hope this helps!
siddhartharao77:
yes.. Wait i will solve it again using 0.7 and 0.4
okk
sir multiple me mistake h
what ?
0.7×0.4=0.28
Yes... It is correct
Kindly refresh the page..I have edited my answer..
So what problem do you have ?
Please tell to me
Thanks for brainliest bro...
Answered by
14
Here is ur answer
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