Question

Solve it correctly : ​In ΔABC angle BAC =90°.Seg AD_l_ side BC. The sides of the triangle are represented by small letters. AD=d ,AB=c,AC=b
Prove that 1/d²=1/b²+1/c²​

Answer 1

Answer:

BAC=90° AD=90°

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Answer 2

Answer: As by, the sides of the triangle are represented by small letters. AD=d ,AB=c,AC=b

Step-by-step explanation: As according to the question,

​In ΔABC angle BAC =90°.

Seg AD _l_ side BC.

The sides of the triangle are represented by small letters. AD=d ,AB=c,AC=b

Prove that 1/d²=1/b²+1/c²​

As $\frac{1}{a^{2} } = \frac{1}{b^{2} } +\frac{1}{c^{2} }$

As WKT AB: AC =BD-DC

So now by bydrogoxs theorem

$\frac{(b^{2}+c^{2}) }{b^{2} c^{2}} =1$

As now $\frac{b^{2}+c^{2} }{b^{2}c^{2} }=\frac{1}{d^{2} }$

SO now $\frac{b^{2} }{b^{2}c^{2} } +\frac{c^{2}}{b^{2}d^{2}} =\frac{1}{d{2} }$

As by dividing $\frac{1}{c^{2} } +\frac{1}{b^{2} } =\frac{x}{y}$

now by solving $\frac{1}{c^{2} } +\frac{1}{b^{2} } =\frac{1}{d^{2} }$

Hence prove,

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