Question

solve it fast as u can​

Answer 1

Answer:

x = 1 , y = -1

Step-by-step explanation:

-------> px + qy = (p-q) .......... (1)

-------> qx - py = (p+q) .............(2)

---->(2) * p,

       pqx - $p^{2}$y = p(p+q) ........... (3)

----> (1) * q,

       pqx + $q^{2}$y = q(p-q)............. (4)

----> (4) - (3)

       $q^{2}$y + $p^{2}$y = q(p-q) - p(p+q)

     ⇒ ( $q^{2}$ + $p^{2}$ ) y= qp - $q^{2}$ - $p^{2}$ - qp

  ⇒ y = $\frac{-(q^{2} +p^{2})}{(q^{2}+p^{2} )}$

⇒ y = -1

------> put y in (1),

        px -q =p -q

       x = 1