Question

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Answer 1

$\color{red}\large\underline{\underline{Given:}}$

• $Volume = 2m × 0.5m × 0.25m$
• $Density = 7.8 g\:cm^{-3} \rightarrow 7800 kg\:m^{-3}$

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$\color{purple}\large\underline{\underline{To\:Find:}}$

• The mass of the block of iron..

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$\color{orange}\large\underline{\underline{Taken:}}$

Let the mass be x.

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$\color{blue}\large\underline{\underline{We\:know:}}$

$Density = \dfrac{Mass}{Volume}$

so , from there we get;

$\therefore Mass = Density × Volume$

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$\color{green}\large\underline{\underline{Solution:}}$

$\Rightarrow x = 7800kg\:m^{-3} × 2m × 0.5m × 0.25m$

$\Rightarrow x = (7800 × 2 × 0.5 × 0.25)kg$

$\Rightarrow x = \bigg(7800 × 2 × \dfrac{5}{10} × \dfrac{25}{100}\bigg)kg$

$\Rightarrow x = \bigg(7800 × 2 × \dfrac{1}{2} × \dfrac{1}{4}\bigg)kg$

$\Rightarrow x = \bigg(7800 × \dfrac{1}{4}\bigg)kg$

$\Rightarrow x = 1950 kg$

${\boxed{Mass = 1950kg}}$

Answer 2

1950 kg is the answer. I hope it will help you