find the orthocenter of a triangle whose vertices are (-2, -1)(6,-1) and (2,5)
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Co-ordinates of the ortho centre O are = [2, 5/3]
Step-by-step explanation:
A(–2, –1) B(6, –1), C(2, 5) are the vertices of ∆ABC Slope of BC = (5 + 1)/ (2 - 6)
= 6/- 4
= - 3/2
AD is perpendicular to BC
Slope of AD = 2/3
Equation of AD is y + 1 = 2/3 (x + 2)
2x – 3y + 1 = 0 —— (1)
Slope of AC = (5 + 1)/ (2 + 2)
= 6/4
= 3/2
BE is perpendicular to AC
Slope of BE = – 2/3
Equation of BE is y + 1 = – 2/3 (x – 6)
2x + 3y – 9 = 0 —— (2)
(next step is on picture)
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