Question

prove that sin⁸theta-cos ⁸ theta=(1-2 cos² theta)(1-2 sin² theta cos² theta)​

Answer 1

Answer:

here it is

sin^8Q-cos^8Q

=(sin^4Q-cos^4Q) (sin^4Q+cos^4Q)

=(sin^2Q-cos^2Q) (sin^2Q+cos^2Q) {(sin^2Q+cos^2Q) ^2 -2sin^2Qcos^2Q}

=(1-cos^2Q-cos^2Q) (1-2sin^2Qcos^2Q)

=(1-2cos^2Q) (1-2sin^2Qcos^2Q)

hence proved

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guys