Question

a ship of mass 4*10^7kg is pulled by a force of 6*10^5 N. Find acceleration of the ship. Also find velocity of ship after it has covered a distance of 300 m. Neglect resistance of sea water

Answer 1

$\mathtt{\huge{ \fbox{Solution :)}}}$

Given ,

• Mass (m) = 4 × (10)^7 kg
• Force (f) = 6 × (10)^5 N
• Initial velocity (u) = 0 m/s²
• Displacement (s) = 300

We know that ,

$\large \mathtt{\fbox{F = ma }}$

Thus ,

$\sf \hookrightarrow 6 \times {(10)}^{5} = 4 \times {(10)}^{7} \times a \\ \\ \sf \hookrightarrow </p><p></p><p>a = 1.5 \times {(10)}^{ - 2} \: \: m/ {s}^{2} </p><p>$

Hence , the acceleration is 1.5 × (10)^-2 m/s²

We know that ,

The third equation of motion is given by

$\large \mathtt{ \fbox{ {(v)}^{2} = 2as + {(u)}^{2} }}$

Thus ,

(v)² = 2 x 1.5 x (10)^-2 × 300 + (0)²

(v)² = 900 × (10)^-2

v = √9

v = 3 m/s

Hence , the final velocity is 3 m/s

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