Question

Solve it:

Find the work done on the object on which a force of 10N acts to displace it through a distance of 3m, at an angle of 60°

Answer 1

Hey mate ^_^

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Answer:
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Work = F. d Cos theta

=> 10 × 3 × Cos 60°

=> 10 × 3 × 1/2

=> 30 × 1/2

=> 15 J

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Answer 2

Hey there!

Answer:


Work done = ?


Force = 10 Newton


Displacement = 3 metre.


Angle = 60°


To find work done: using formulla ;


w = f × d × cos$\theta$


Substituting values ( Given above )


w = 10 × 3 × cos60°


We know cos60° = 1/2


w = 30 × 1/2


w = 15 joules( J ).



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