Solve it:
Find the work done on the object on which a force of 10N acts to displace it through a distance of 3m, at an angle of 60°
Answers
Answered by
21
Hey mate ^_^
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Answer:
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Work = F. d Cos theta
=> 10 × 3 × Cos 60°
=> 10 × 3 × 1/2
=> 30 × 1/2
=> 15 J
#Be Brainly❤️
=======
Answer:
=======
Work = F. d Cos theta
=> 10 × 3 × Cos 60°
=> 10 × 3 × 1/2
=> 30 × 1/2
=> 15 J
#Be Brainly❤️
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yes or no
Answered by
3
Hey there!
Answer:
Work done = ?
Force = 10 Newton
Displacement = 3 metre.
Angle = 60°
To find work done: using formulla ;
w = f × d × cos
Substituting values ( Given above )
w = 10 × 3 × cos60°
We know cos60° = 1/2
w = 30 × 1/2
w = 15 joules( J ).
#TogetherWeGoFar
Answer:
Work done = ?
Force = 10 Newton
Displacement = 3 metre.
Angle = 60°
To find work done: using formulla ;
w = f × d × cos
Substituting values ( Given above )
w = 10 × 3 × cos60°
We know cos60° = 1/2
w = 30 × 1/2
w = 15 joules( J ).
#TogetherWeGoFar
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