solve it find theta
I think it is quadratic
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we will write cos^2$ = 1 - sin^2$
now we get 4(1 - sin^2$) + 2 ( 3^1/2 + 1 )sin$ =4(3^1/2)
simplify
= 4-4sin^2$ + 2(3^1/2 + 1 )sin$ - 4(3^1/2)=0
= -4sin^2$ + 2(3^1/2 +1 )sin$ - 4(3^1/2 - 1)
further it can be solved by splitting mid term
now we get 4(1 - sin^2$) + 2 ( 3^1/2 + 1 )sin$ =4(3^1/2)
simplify
= 4-4sin^2$ + 2(3^1/2 + 1 )sin$ - 4(3^1/2)=0
= -4sin^2$ + 2(3^1/2 +1 )sin$ - 4(3^1/2 - 1)
further it can be solved by splitting mid term
Krish6990:
will you provide me photo of the method on page
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