Question

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Answer 1

Answer:

I have attached above the solution

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Answer 2

Explanation:

$\bold{Given - } \\ \bold{u } = 54 \: kmh {}^{ - 1} \\ \implies \frac{ \cancel{54} \times 10 \cancel{00}}{ \cancel{6} \cancel{0} \times 6 \cancel{0} } \\ \implies \frac{9 \times 10}{6} \\ \implies15 \: m{s}^{ - 1} \\ \bold{u = } \: 15 \: ms {}^{ - 1} \bold{( initial \: velocity)} \\ \\ \bold{v = } \: 72 \: km {h}^{ - 1} \\ \implies \frac{ \cancel{72} \times 10 \cancel{00}}{ \cancel{60} \times \cancel{60} } \\ \implies20 \: m{s}^{ - 1} \\ \bold{v = } \: 20 \: ms {}^{ - 1} \: \bold{(final \: velocity)} \\ \bold{t = } \: 15 \: s \: \bold{(time)} \\ \\ \bold{To \: find - } \\ {acc}^{n} = {?} \\ \\ Now, \\ \bold{v = u + at} \\ \implies20 = 15 + 15 \bold{a} \\ \implies20 - 15 = 15 \bold{a} \\ \implies5 = 15 \bold{a} \\ \implies \bold{a} = \cancel{\frac{ 5}{15} } \\ \implies \bold{a} = \frac{1}{ 3} \: m{s}^{ - 2} \\ \\ Hence, \\ \bold{acc {}^{n} = 0.33 \: m{s}^{ - 2} }$