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6u+3v=7uv .... (1)
3u+9v=11uv .... (2)
multiply (1) by 3 we get
18u+9v=21uv ... (3)
subtract(2) from (3) we get
15u=10uv
v=15u/10u
v=3/2
3u+9v=11uv .... (2)
multiply (1) by 3 we get
18u+9v=21uv ... (3)
subtract(2) from (3) we get
15u=10uv
v=15u/10u
v=3/2
Answered by
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Hi ,
6u + 3v = 7uv-----( 1 )
3u + 9v = 11uv-----( 2 )
Multiply equation ( 2 ) with 2 we get,
6u + 18v = 22uv ----( 3 )
Sutract equation ( 1 ) from
equation ( 2 ), we get ,
15v = 15uv
15v / 15v = u
1 = u
u = 1
Put u = 1 in equation ( 1 ) , we get
6 + 3v = 7v
3v - 7v = - 6
- 4v = -6
v = ( -6 ) / ( - 4 )
v = 3/2
Therefore ,
u = 1 , v = 3/2
I hope this helps you.
:)
6u + 3v = 7uv-----( 1 )
3u + 9v = 11uv-----( 2 )
Multiply equation ( 2 ) with 2 we get,
6u + 18v = 22uv ----( 3 )
Sutract equation ( 1 ) from
equation ( 2 ), we get ,
15v = 15uv
15v / 15v = u
1 = u
u = 1
Put u = 1 in equation ( 1 ) , we get
6 + 3v = 7v
3v - 7v = - 6
- 4v = -6
v = ( -6 ) / ( - 4 )
v = 3/2
Therefore ,
u = 1 , v = 3/2
I hope this helps you.
:)
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