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x(x - 2)(x – 4) + 4x – 8
Answers
Answer:
x(x-2)(x-4)+4x-8
x(x-2)(x-4)+4(x-2)
(x-2)[x(x-4)+4]
(x-2)[x²-4x+4]
(x-2)[x²-2x-2x+4]
(x-2)(x-2)(x-2)
(x-2)³
Answer:
Required result is ( x - 2 )^3.
Step-by-step explanation:
Case 1 : If we have to factorise it : -
= > x( x - 2 )( x - 4 ) + 4x - 8
= > x( x - 2 )( x - 4 ) + 4( x - 2 )
= > ( x - 2 )[ x( x - 4 ) + 4 ]
= > ( x - 2 )[ x^2 - 4x + 4 ]
= > ( x - 2 )[ x^2 - ( 2 + 2 )x + 4 ]
= > ( x - 2 )[ x^2 - 2x - 2x + 4 ]
= > ( x - 2 )[ x( x - 2 ) - 2( x - 2 ) ]
= > ( x - 2 )( x - 2 )( x - 2 )
= > ( x - 2 )^3
Hence the required value is ( x - 2 )^3.
Case 2 : If we have expand this : -
= > x( x - 2 )( x - 4 ) + 4x - 8
= > x[ x( x - 4 ) - 2( x - 4 ) ] + 4x - 8
= > x[ x^2 - 4x - 2x + 8 ] + 4x - 8
= > x^3 - 4x^2 - 2x^2 + 8x + 4x - 8
= > x^3 - 6x^2 + 12x - 8
Hence the required value is x^3 - 6x^2 + 12x - 8.