solve it if u can ;p :- let a and b be positive integers. show that √2 lies between a/b and (a+2b)÷(a+b)
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heyy frnd!!
A correct formulation would be
Considering 0<a,0<b for {a,b}∈R
If
ab<√2 then √2<a+2ba+b
because
Making a=λb we have
λ<√2<λ+2λ+1=1+1λ+1
Here f(λ)=1+1λ+1 is a decreasing function for λ>0 and f(√2)=1+1√2+1=√2 so we conclude that
for 0<λ<√2⇒f(λ)>√2
i hope this helps u
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source : phd textbooks :)
Anonymous:
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