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If (3k+2 , 2k-1) are ordered pair of equation 4x-3y+1=0 , find k.
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=> 4x-3y+1=0
=> 4(3k+2) - 3(2k-1) +1 = 0
=> 12k +8 -6k + 3 + 1 = 0
=> 6k +12 = 0
=> k = -12/6 = -2
=> k = -2
=> 4(3k+2) - 3(2k-1) +1 = 0
=> 12k +8 -6k + 3 + 1 = 0
=> 6k +12 = 0
=> k = -12/6 = -2
=> k = -2
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