Solve it immediately cot B+C/2=tanA/2
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In ∆ ABC
angle A+B+C = 180° (Angle sum property)
B+C = 180-A
divide by 2 both side
B+C/2 = 90- A/2
taking cot both side
cot (B+C)/2 = cot(90-A/2)
cot(B+C)/2 = tan(A/2)
angle A+B+C = 180° (Angle sum property)
B+C = 180-A
divide by 2 both side
B+C/2 = 90- A/2
taking cot both side
cot (B+C)/2 = cot(90-A/2)
cot(B+C)/2 = tan(A/2)
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