Question

solve it in expandation form

x^2 - 17x + 16​

Answer 1

Answer:

x^2-16x-x+16

x(x-16)-1(x-16)

(x-16)(x-1)

x=16 or x=1

Step-by-step explanation:

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Answer 2

Hey MaTe!!!

${x}^{2} - 17x + 16 \\ \\ = > {x}^{2} - 16x - x + 16 \\ \\ x(x - 16) - 1(x - 16) \\ \\ (x - 16)(x -1 )$

Hence, value of x can be - 16, 1

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