Question

solve it its urgent​

Answer 1

Solution:-

$\implies \: a {d}^{2} ( \frac{ax}{b} + \frac{2c}{d})x + b {c}^{2} = 0 \\ \\ \implies \: a {d}^{2} x( \frac{ax}{b} + \frac{2c}{d} ) + b {c}^{2} = 0 \\ \\ \implies \: \frac{ {a}^{2} {d}^{2} {x}^{2} }{b} + \frac{2ac {d}^{2} x}{b} + b {c}^{2} = 0 \\ \\ \implies \: \frac{ {a}^{2} {d}^{2} {x}^{2} }{b} + 2acdx + b{c}^{2} = 0 \\ \\ \implies \: {a}^{2} {d}^{2} {x}^{2} + 2abcdx + {b}^{2} {c}^{2} = 0 \\ \\ \implies \: {(adx + bc)}^{2} = 0 \\ \\ \implies \: adx + bc = 0 \\ \\ \implies \: adx = - bc \\ \\ \implies \: x = \frac{ - bc}{ad}$

Using identify :-

a² + b² + 2ab = (a+b)^2

Hence proved

Answer 2

Refers to attachment....!!!

hope IT HELPs....