Math, asked by harsh272008, 8 months ago

solve it its urgent​

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Answered by anshi60
15

Solution:-

\implies \: a {d}^{2} ( \frac{ax}{b}  +  \frac{2c}{d})x +  b {c}^{2}   = 0 \\  \\ \implies \: a {d}^{2} x( \frac{ax}{b}  +  \frac{2c}{d} ) + b {c}^{2}  = 0 \\  \\ \implies  \:  \frac{ {a}^{2} {d}^{2}  {x}^{2}  }{b}  +  \frac{2ac {d}^{2} x}{b}  + b {c}^{2}  = 0 \\  \\  \implies \:  \frac{ {a}^{2} {d}^{2}  {x}^{2}  }{b}  + 2acdx +  b{c}^{2}  = 0 \\  \\ \implies \:  {a}^{2}  {d}^{2}  {x}^{2}  + 2abcdx +  {b}^{2}  {c}^{2}  = 0 \\  \\ \implies \:  {(adx + bc)}^{2}  = 0 \\  \\ \implies \: adx + bc = 0 \\  \\ \implies \: adx =  - bc \\  \\  \implies \: x =  \frac{ - bc}{ad}

Using identify :-

a² + b² + 2ab = (a+b)^2

Hence proved

Answered by radhika0106
12

Refers to attachment....!!!

hope IT HELPs....

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Anonymous: Thank you very much :)
radhika0106: : )
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