Question

Solve it (k²-13 k-30) ÷ ( k+ 2)​

Answer 1

Step-by-step explanation:

answer:-

Factoring k2+13k-30

The first term is, k2 its coefficient is 1 .

The middle term is, +13k its coefficient is 13 .

The last term, "the constant", is -30

Step-1 : Multiply the coefficient of the first term by the constant 1 • -30 = -30

Step-2 : Find two factors of -30 whose sum equals the coefficient of the middle term, which is 13 .

-30 + 1 = -29

-15 + 2 = -13

-10 + 3 = -7

-6 + 5 = -1

-5 + 6 = 1

-3 + 10 = 7

-2 + 15 = 13 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -2 and 15

k2 - 2k + 15k - 30

Step-4 : Add up the first 2 terms, pulling out like factors :

k • (k-2)

Add up the last 2 terms, pulling out common factors :

15 • (k-2)

Step-5 : Add up the four terms of step 4 :

(k+15) • (k-2)

Which is the desired factorization