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Answers
Area of FEH = 1/2 × base × height
= 1/2 × 40 × 80
= 1600 m²
Area of CDEI = breadth × length
= 100 × (80 + 80) = 100 × 160
= 16000 m²
Draw imaginary lines from points F and B which are perpendicular to GJ and IC respectively. Mark the intersection as F' and B'. Now the shape is divided into a triangle and a rectangle.
Area of FHJF' = breadth × length
= 40 × (80 + 80) = 40 × 160
= 6400 m²
Area of FGF' = 1/2 × base × height
= 1/2 × 120 × 160
= 9600 m²
Area of BKIB' = breadth × length
= 60 × (80 + 40) = 60 × 120
= 7200 m²
Area of BCB' = 1/2 × base × height
= 1/2 × 40 × 120
= 2400 m²
Area of GJA = 1/2 × base × height
= 1/2 × 160 × 100
= 8000 m²
Area of GJA = 1/2 × base × height
= 1/2 × 60 × 60
= 1800 m²
Total area of the field = 1600 + 16000 + 6400 + 9600 + 7200 + 2400 + 8000 + 1800
= 53000m²