Question

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Answer 1

Step-by-step explanation:

(i) From the given figure, we can write as

ZACD + ZACB = 180° is a linear pair

On rearranging we get

ZACB = 180°-112° = 68°

Again from the figure we have,

ZBAE + ZBAC = 180° is a linear pair

On rearranging we get, ZBAC = 180°-120° = 60°

We know that the sum of all angles of a triangle is 180°.

Therefore, for AABC:

x + <BAC+ ZACB = 180°

x = 180° -60° -68° = 52°

x = 52°

(ii) From the given figure, we can write as

ZABC + 120° = 180° is a linear pair

ZABC = 60°

Again from the figure we can write as

ZACB+ 110°= 180° is a linear pair

ZACB = 70°

We know that the sum of all angles of a triangle is 180°. Therefore, consider AABC, we get x+ZABC+ZACB = 180°

x = 50°