Question

solve it out ASAP
this is a que from rd sharma
​

Answer 1

Answer:

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Answer 2

$\\ \\ \frac{1}{3 - \sqrt{8} } - \frac{1}{ \sqrt{8} - \sqrt{7} } + \frac{1}{ \sqrt{7} - \sqrt{6} } - \frac{1}{ \sqrt{6} - \sqrt{5} } + \frac{1}{ \sqrt{5} - 2} \\ \\ \\ \implies \frac{3 + \sqrt{8} }{(3 - \sqrt{8} )(3 + \sqrt{8}) } - \frac{ \sqrt{8} + \sqrt{7} }{( \sqrt{8} + \sqrt{7} )( \sqrt{8} - \sqrt{7} ) } + \frac{ \sqrt{7} + \sqrt{6} }{( \sqrt{7} + \sqrt{6} )( \sqrt{7} - \sqrt{6} ) } - \frac{ \sqrt{6} + \sqrt{5} }{( \sqrt{6} - \sqrt{5} )( \sqrt{6} + \sqrt{5}) } + \frac{ \sqrt{5} + \sqrt{4} }{( \sqrt{5} + \sqrt{4} )( \sqrt{5} - \sqrt{4} ) } \\ \\ \\ \implies \sqrt{9} + \sqrt{8} - \sqrt{8} - \sqrt{7} + \sqrt{7} + \sqrt{6} - \sqrt{6} - \sqrt{5} + \sqrt{5} + \sqrt{4} \\ \\ \\ \implies \sqrt{9} + \cancel{\sqrt{8}} - \cancel{ \sqrt{8}} - \cancel{ \sqrt{7}} + \cancel{ \sqrt{7} } + \cancel{ \sqrt{6} } - \cancel{\sqrt{6}} - \cancel{\sqrt{5} } + \cancel{ \sqrt{5} } + \sqrt{4} \\ \\ \\ \Large \therefore \: \: \rightsquigarrow \:\: \bf 5 \: \: \: \: \: \: ans.$