Question

solve it please....4th one

Answer 1

Let the no. in tens place be 'y' and in ones place be 'x'

Situation 1:

( 10x + y ) / ( x + y ) = 7

10x + y = 7( x + y)

10x + y = 7x + 7y

10x - 7x = 7y - y

3x = 6y

3x - 6y = 0

/2 = x - 2y = 0 .......(1)


Situation 2: 

10x + y - 27 = 10y - x

10x + x = 10y - y +27

11x = 9y + 27

11x - 9y = 27 ......(2)

(2) - (1) =

(2)        = 11x - 9y = 27
(1) * 11 = 11x - 22y = 0     (-)
    Ans. =        13y = 27 

         y = 27/13  .....(3)

Applying (3) in (1),
       
x - 2*(27/13) = 0
       
x - 54/13       = 0 

x = 54/13     .....(4)

The two digit no. is 10x + y

From (3) and (4),

10*(54/13) + 27/13 = (540 + 27) / 13 
                               = 567 / 13
                               = 43.61

Hope it helps! Thanq!!

Answer 2

give her brainliest
;-)