Question

solve it please!! solve it please solve it please

Answer 1

Hello,
x²+5x-(a²+a-6)=0;
∆=5²+4•(a²+a-6)=25+4a²+4a-24=4a²+4a+1;
x₁,₂=-5± √∆/2=-5±√4a²+4a+1/2
=-5±√(2a+1)²/2=-5±(2a+1)/2
then
x₁=-5-(2a+1)/2=-5-2a-1/2=-2a-6/2=2(-a-3)/2=-a-3;
and
x₂=-5+(2a+1)/2=-5+2a+1/2=2a-4/2=2(a-2)/2=a-2

Bye :-)