Question

solve it please urgent......
attempt only if you know how to solve pls if you don't know then don't waste your and my time. Thank you.

Answer 1

(1)
$y = {x}^{x} + {a}^{a}$
see a^a is constant hence it's differentiation =0
so
y=x^x +a^a
let it
y=x^x
take log
logy=xlogx
differentiate
(1/y)(dy/dx)=logx+x(1/x)::::::::::(1)
dy/dx=y(logx+1)
dy/dx=(x^x+a^a)(logx+1)

$(2).y = {x}^{x} + {a}^{x} + {x}^{a} + {a}^{a}$
let m=x^x
dm/dx=x^x(1+logx)....(from(1))
let n=a^x
logn=xloga
(1/n)(dn/dx)=loga
dn/dx=a^x(loga),,,,,,(2)
let p =x^a
dp/dx=ax^(a-1).....(3)
let r=a^a
dr/dx=0......(4)
Now question becomes
y=m+n+p+r
differentiate
dy/dx=dm/dx + dn/dx +dp/dx +dr/dx
put the value from (1)(2)(3)(4)
dy/dx=x^x(1+logx)+a^x(loga)+ax^(a-1)+0

Answer 2

Hope...This will help you...☺️...