Solve it pls
It's urgent Help me
I will mark the right answer as brainliest Pls
Answers
Step-by-step explanation:
Quadratic Polynomial = k(x²-(sum of roots)x+product of roots)
Sum of roots given = √2
Product of roots given = -3/2
Therefore polynomial is k(x²-√2x-3/2)
= k((2x²-2√2x-3)/2)
Let k = 2
Therefore polynomial is 2x²-2√2x-3
For its roots
Using factorisation
2x²-(3√2-√2)x-3 = 0
2x²-3√2x+√2x-3=0
2x(x-3/√2)+√2(x-3/√2) = 0
(x-3/√2) (2x+√2)= 0
x = -1/√2 and 3/√2
Answer:
Mark as brainliest answer.
Step-by-step explanation:
→ The correct answer is (A) 2x² - 2√2x - 3
→ Explanation :
→ sum of roots
→ α + β
→ -b/a
→ product of roots
→ αβ
→ c/a
→ Now we have to just check the equation from the option given below that satisfies the above sum of roots & product of roots.
→ Let us take first equation
→ 2x² - 2√2 - 3
→ sum of roots = -b/a = -(-2√2)/2 = √2
→ product of roots = c/a = -3/2
→ We can see that the value we get is satisfied in the option A so correct answer is option (A).