Question

solve it plz................. ​

Answer 1

$\begin{gathered}\begin{gathered}\sf \large \red{\underline{ Question:-}}\\\\\end{gathered}\end{gathered}$

• Find the gravitational force between Earth and moon.

GIVEN-:

$\begin{gathered}\begin{gathered}\pink{ \frak{Given}} \begin{cases} \sf \: Me \: =\: 6 \: × 10^24\:kg \\ \\ \sf \: Mm \: = \: 7.4\: ×10^22 \:kg\ \\ \sf \: D\: = \: 3.84 \: × 10^5 \: km \\ \\ \sf \end{cases} \\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}\sf \large \red{\underline{ To find -;}}\\\\\end{gathered}\end{gathered}$

• Gravitational force between Earth and moon

$\begin{gathered}\begin{gathered}\sf \large \red{\underline{ Solution-;}}\\\\\end{gathered}\end{gathered}$

$g = \frac{6.7 \times {10}^{ - 11} \times 6 \times {10}^{24} \times 10 }{(6.4 \times {10b})^{2} }$

$= \frac{6.7 \times 6 \times {10}^{13} \times 10 }{6.4 \times 6.4 \times {10}^{12} }$

$= \frac{6.7 \times 6 \times 10}{6.4 \times 6.4}$

$= \frac{402}{40.96}$$\begin{gathered}\begin{gathered}: \implies \underline{ \boxed{\displaystyle \sf \bold{\:g=9.814\: ms ^{ 2} }} }\\ \\\end{gathered}\end{gathered}$

HOPES IT HELPS YOU

Answer 2

Given:

$\sf{{M_E=6 \times}{{10}^24}kg}$

$\sf{{M_M=7.4\times}{{10}^22}kg}$

$\sf{{D=3.84 \times}{{10}^5}km}$

To Find:

Gravitational force between Earth and moon.

Solution:

$\sf{F=}{\dfrac{G m_1 m_2}{r^2}}$

$\sf{F=}{\dfrac{(6.7 \times{{10}^{-11}})(6 \times{{10}^{24}})(7.4 \times{{10}^{22}})}{(3.84 \times{{10}^5})^2}}$

$\sf{F=}{\dfrac{6.7\times 6\times 7.4}{14.7456}}{{10}^{19}}$

$\sf{F=20.17\times{{10}^{19}}}$

$\sf{F=2.01\times{{10}^{20}}N}$

Gravitational force between earth and moon is equal to $\sf{2.01\times{{10}^{20}}N}$.