Math, asked by rajneeshmanpreeet, 11 months ago

Solve it
Plz freinds don't copy from any web site. ​

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Answers

Answered by Anonymous
3

Answer:

❤️ Hey mate ❤️

Your solution is in the given pic ✖️

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Answered by Anonymous
23

Question :

i) (4x - 3y + 2z) (16x² + 9y² + 4z² + 12xy + 6yz - 8zx)

ii) (2x - y + 3z) (4x² + y² + 9z² + 2xy + 3yz - 6zx)

Solution :

i) (4x - 3y + 2z) (16x² + 9y² + 4z² + 12xy + 6yz - 8zx)

→ [(4x)² + (-3y)² + (2z)²] [(4x)² + (-3y)² + (2z)² - (4x) (-3y) - (-3y) (2z) - (2z) (4z)]

→ (4x)³ + (-3y)³ + (2z)³ - 3(4x) (-3y) (2z)

→ 64x³ - 27y³ + 8z³ + 72xyz

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ii) (2x - y + 3z) (4x² + y² + 9z² + 2xy + 3yz - 6zx)

→ [(2x)² + (-y)² + (3z)²] [(2x)² + (y)² + (3z)² - (2x) (-y) + (-y) (3z) + (-y) (3z) - (3z) (2x)]

→ (2x)³ + (-y)³ + (3z)³ - 3(2x) (-y) (3z)

→ 8x³ - y³ + 9z³ - 18xyz.

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i) 64x³ - 27y³ + 8z³ + 72xyz

ii) 8x³ - y³ + 9z³ - 18xyz.

_________ [ ANSWER ]

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