Question

solve it plz...... kl exam h

Answer 1

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$\alpha + \beta = 0 \\ \\ \alpha \beta = - 1 \\ \\ therefore. \\ \\ quadratic \: equation : \\ \\ {x}^{2} - ( \alpha + \beta)x + \alpha \beta \\ \\ \: then \\ \\ {x}^{2} - (0)x + ( - 1) \\ \\ {x}^{2} - 1$
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