Math, asked by anmolshakyaujajajaj, 2 months ago

Solve:
it plz urgent​

Attachments:

Answers

Answered by ritikakeshri2005
2

Answer:

a) (x-1)(x-3) =15

x²-3x-x+3=15

x²-4x+3=15

x²-4x+3-15=0

x²-4x-12=0

x²-6x+2x-12=0

x(x-6)+2(x-6)=0

(x-6)(x+2)=0

x=6 or x=-2

Answered by amansharma264
4

EXPLANATION.

(1) = (x - 1)(x - 3) = 15.

As we know that,

⇒ x² - 3x - x + 3 = 15.

⇒ x² - 4x + 3 - 15 = 0.

⇒ x² - 4x - 12 = 0.

Factorizes the equation into middle term splits, we get.

⇒ x² - 6x + 2x - 12 = 0.

⇒ x(x - 6) + 2(x - 6) = 0.

⇒ (x + 2)(x - 6) = 0.

x = - 2 & x = 6.

(2) = x(3x + 1) = 4.

As we know that,

⇒ 3x² + x - 4 = 0.

Factorizes the equation into middle term splits, we get.

⇒ 3x² + 4x - 3x - 4 = 0.

⇒ x(3x + 4) - 1(3x + 4) = 0.

⇒ (x - 1)(3x + 4) = 0.

x = 1 & x = -4/3.

(3) = x + 1/x = 10/3, x ≠ 0.

As we know that,

⇒ x² + 1/x = 10/3.

⇒ 3(x² + 1) = 10x.

⇒ 3x² + 3 - 10x = 0.

⇒ 3x² - 10x + 3 = 0.

Factorizes the equation into middle term splits, we get.

⇒ 3x² - 9x - x + 3 = 0.

⇒ 3x(x - 3) - 1(x - 3) = 0.

⇒ (3x - 1)(x - 3) = 0.

x = 1/3 & x = 3.

(4) = 2x - 3/x = 5, x ≠ 0.

As we know that,

⇒ 2x² - 3/x = 5.

⇒ 2x² - 3 = 5x.

⇒ 2x² - 3 - 5x = 0.

⇒ 2x² - 5x - 3 = 0.

Factorizes the equation into middle term splits, we get.

⇒ 2x² - 6x + x - 3 = 0.

⇒ 2x(x - 3) + 1(x - 3) = 0.

⇒ (2x + 1)(x - 3) = 0.

x = -1/2 & x = 3.

(5) = (x + 3)/(x + 2) = (3x - 7)/(2x - 3), x ≠ 2, 3/2.

As we know that,

⇒ (x + 3)(2x - 3) = (3x - 7)(x + 2).

⇒ 2x² - 3x + 6x - 9 = 3x² + 6x - 7x - 14.

⇒ 2x² + 3x - 9 = 3x² - x - 14.

⇒ 3x² - x - 14 - 2x² - 3x + 9 = 0.

⇒ 3x² - 2x² - x - 3x - 14 + 9 = 0.

⇒ x² - 4x - 5 = 0.

Factorizes the equation into middle term splits, we get.

⇒ x² - 5x + x - 5 = 0.

⇒ x(x - 5) + 1(x - 5) = 0.

⇒ (x + 1)(x - 5) = 0.

x = - 1 & x = 5.

(6) = (2x)/(5 - 3x) = (5 + 3x)/(8x), x ≠ 0, 5/3.

As we know that,

⇒ (2x)(8x) = (5 + 3x)(5 - 3x).

⇒ 16x² = (5)² - (3x)².

⇒ 16x² = 25 - 9x².

⇒ 16x² + 9x² = 25.

⇒ 25x² = 25.

⇒ x² = 1.

x = ± 1.

Similar questions