Question

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Answer 1

$\huge\purple{◆question◆}$

★Two towers AB and CD are situated at a distance 'd' apart. AB is 20m high and CD is 30m. An object of mass m is thrown from AB horizontally at 10m/s. At the same time, an object of mass 2m is thrown from top CD at an angle 60degree with the horizontal towards AB with the same magnitude of initial velocity as first. The objects collide in mid air & stick to each other.

$\huge\purple{◆solution◆}$

d = 10√3 m

40/3 m above ground

An object of mass m is thrown from AB horizontally at 10m/s.

AB is 20m high

so Object will always be aat height less than 20 m from ground to be in the air

Time to reach at ground

20 = (1/2)gT² => T² = 4 => T = 2 Sec

in 0 to 2 sec Both objects should collide

Distance Covered in T Sec = (1/2)*10*T² = 5T²

Other object thrown at angle 60 deg with 10 m/s

vertical Velocity = 10 Sin60 = 5√3

Distance Covered in T Sec = 5√3T + (1/2)*10T² = 5√3T + 5T²

5√3T + 5T² = 10 + 5T² ( as CD is 10 m more height then AB)

=> T = 2/√3

5T² = 5(2/√3)² = 20/3 (20 - 20/3) = 40/3 m above Ground

Horizontal Covered = 10 * 2/√3 = 20/√3

Horizontal Covered = 5*2/√3 = 10/√3

Total Horizontal Distance = 20/√3 + 10/√3 = 30/√3 = 10√3

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Answer 2

Answer:

u need the full form of DC

ur answer is Devyani Chouhan ..its me haha i was joking ..

FULL FORM IS ;

Direct current

another is ;

Deputy Commissioner