Math, asked by rana9910, 1 year ago

solve it plzzzz if any one

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Answered by DevyaniKhushi
0

x = 3 +  \sqrt{3}  \\  \\  {x}^{2} +  \frac{9}{ {x}^{2} }  = ( {3 +  \sqrt{3} })^{2}  +  \frac{9}{(3 + \sqrt{3}) ^{2} }
(3^{1}  +  {3}^{ \frac{1}{2} })^{2}  +  \frac{9}{(3^{1}  +  {3}^{ \frac{1}{2} })^{2}} \\  \\ ( {3}^{1 +  \frac{1}{2} } )^{2} +  \frac{9}{( {3}^{1 +  \frac{1}{2} } )^{2}}  \\  \\  ({3}^{ \frac{3}{2}}) ^{2}  +  \frac{9}{ ({3}^{ \frac{3}{2}}) ^{2}}   \\  \\  {3}^{ \frac{3}{2} \times 2 } \times  \frac{9}{{3}^{ \frac{3}{2} \times 2 }}  \\  \\  {3}^{3}  +  \frac{9}{ {3}^{3} }  \\  \\ 27 +  \frac{9}{27}  =  \frac{729 + 9}{27}  =  \frac{738}{27}  = 27.33 \\
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