Math, asked by TheKnowledge, 1 year ago

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Answered by Shreya2001
10
HELLO !

★ HERE IS YOUR ANSWER ★

1) L.H.S.


sin2Acos2B - cos2Asin2B

sin2A(1-sin2B) - (1-sin2A)sin2B

sin2A - sin2Asin2B - sin2B + sin2Asin2B

sin2A -sin2B = R.H.S

Since, L.H.S = R.H.S
Hence, Proved ☺

♥ THANK YOU ♥

Shreya2001: Thanks
Answered by rohitkumargupta
11
HELLO DEAR,

sin²Acos²B - cos²Asin²B

==> sin²A(1 - sin²B) - (1 - sin²A)sin²B

==> sin²A - sin²Asin²B - sin²B + sin²Asin²B


==>sin²A - sin²B


I HOPE ITS HELP YOU DEAR,
THANKS

rohitkumargupta: :-)
rohitkumargupta: hehhe
rohitkumargupta: thanks thanks
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