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Answered by
10
HELLO !
★ HERE IS YOUR ANSWER ★
1) L.H.S.
sin2Acos2B - cos2Asin2B
sin2A(1-sin2B) - (1-sin2A)sin2B
sin2A - sin2Asin2B - sin2B + sin2Asin2B
sin2A -sin2B = R.H.S
Since, L.H.S = R.H.S
Hence, Proved ☺
♥ THANK YOU ♥
★ HERE IS YOUR ANSWER ★
1) L.H.S.
sin2Acos2B - cos2Asin2B
sin2A(1-sin2B) - (1-sin2A)sin2B
sin2A - sin2Asin2B - sin2B + sin2Asin2B
sin2A -sin2B = R.H.S
Since, L.H.S = R.H.S
Hence, Proved ☺
♥ THANK YOU ♥
Shreya2001:
Thanks
Answered by
11
HELLO DEAR,
sin²Acos²B - cos²Asin²B
==> sin²A(1 - sin²B) - (1 - sin²A)sin²B
==> sin²A - sin²Asin²B - sin²B + sin²Asin²B
==>sin²A - sin²B
I HOPE ITS HELP YOU DEAR,
THANKS
sin²Acos²B - cos²Asin²B
==> sin²A(1 - sin²B) - (1 - sin²A)sin²B
==> sin²A - sin²Asin²B - sin²B + sin²Asin²B
==>sin²A - sin²B
I HOPE ITS HELP YOU DEAR,
THANKS
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