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In the figure there are two triangles which are triangle BCO and triangle ADO.
Now,
In both the triangles
Angle OBC=Angle OAD [each are of 90°(given)]
AD=BC [Given]
Angle BCO=Angle ADO [Alternate angles as BC//AD]
So, triangle BCO is congruent to triangle ADO
Hence, AO=OB [Corresponding parts of congruent triangles]
Hence, CD bisects AB
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