Question

Solve it

tan^-1 x / √a² - x²

Answer 1

Differentiation ?

$y=\frac{tan^{-1}x}{\sqrt{a^2-x^2}}\\\\\frac{dy}{dx}=\frac{1}{\sqrt{a^2-x^2}}*\frac{1}{1+x^2}+ tan^{-1}x \: * \frac{-1}{2} * \frac{-2x}{(a^2-x^2)^{\frac{3}{2}}}$
   
If the question is different like:

integration of   (tan^-1 x/a)  / √(a² + x²)    then

answer :
     let x = a tanФ..    dx = a sec² Ф dФ
     answer = integral of  Ф secФ dФ
     use integration by parts to get it...