Solve it: tan105=tan (45+60)
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We know that Tan(A + B) = (TanA + TanB)/(1-TanATanB)
tan 105° = Tan(60°+ 45°) = (Tan60° + Tan45°)/(1-Tan 60° Tan45°)
tan 105° = (√3 + 1) / (1 - √3)
tan 105° = Tan(60°+ 45°) = (Tan60° + Tan45°)/(1-Tan 60° Tan45°)
tan 105° = (√3 + 1) / (1 - √3)
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