the sum of a number and its reciprocal is 10/ 3 find the numbers
Answers
Answered by
8
The sum of a number and its reciprocal is 10/ 3 find the numbers
let the number be x
ACQ,
x + 1/x = 10/3
(x²+1)/x = 10/3
now lets cross multiply it........
3x² +3 = 10x
3x²*10x + 3 = 0
3x² -9x- x + 3 =0
(x-3) (x-(1/3)) = 0
hence x = 3 or 1/3
:)
let the number be x
ACQ,
x + 1/x = 10/3
(x²+1)/x = 10/3
now lets cross multiply it........
3x² +3 = 10x
3x²*10x + 3 = 0
3x² -9x- x + 3 =0
(x-3) (x-(1/3)) = 0
hence x = 3 or 1/3
:)
Answered by
6
Heya !!!
Let a number be X .
Reciprocal of X is 1/X.
According to question,
X + 1/X = 10/3
X² + 1 / X = 10/3
3 ( X² + 1) = 10X
3X² + 3 = 10X
3X² - 10X + 3 = 0
3X² - 9X - X + 3 = 0
3X ( X - 3 ) - 1 ( X - 3 ) = 0
( X -3) ( 3X -1) = 0
( X -3) = 0 OR (3X -1) = 0
X = 3 OR X = 1/3
Hence,
Numbers are 3 and 1/3.
★ HOPE IT WILL HELP YOU ★
Let a number be X .
Reciprocal of X is 1/X.
According to question,
X + 1/X = 10/3
X² + 1 / X = 10/3
3 ( X² + 1) = 10X
3X² + 3 = 10X
3X² - 10X + 3 = 0
3X² - 9X - X + 3 = 0
3X ( X - 3 ) - 1 ( X - 3 ) = 0
( X -3) ( 3X -1) = 0
( X -3) = 0 OR (3X -1) = 0
X = 3 OR X = 1/3
Hence,
Numbers are 3 and 1/3.
★ HOPE IT WILL HELP YOU ★
Similar questions