Question

solve it.

${(\frac{3}{27})}^{x} \times {(\frac{3}{27})}^{2x} = \frac{3}{27}$

Answer 1

➡HERE IS YOUR ANSWER⬇

${(\frac{3}{27})}^{x} \times {(\frac{3}{27})}^{2x} = \frac{3}{27} \\ \\ or \: \: {(\frac{3}{27})}^{x + 2x} = \frac{3}{27} \: \: \: since \: {a}^{m} \times {a}^{n} = {a}^{m + n} \\ \\ or \: \: {(\frac{3}{27})}^{3x}= ( { \frac{3}{27} })^{1} \\ \\ now \: \: comparing \: \: we \: \: get \\ 3x = 1 \\ \\ hence \: \: x = \frac{1}{3}$

⬆HOPE THIS HELPS YOU⬅

Answer 2

ANSWER IN THE ATTACHMENT
HOPE IT HELPS
MARK AS BRAINLIEST