Question

Solve it.
$\textsf{Let }a_1,a_2,.....a_{30} \textsf{ be an AP.} S = \displaystyle \sum_{i=1}^{30} a_i \textsf{ and }T = \displaystyle \sum_{i=1}^{15} a(2i-1). \textsf{If }a_5 =27 \ and \ S - 2T = 75;\textsf{Find } a_10.$

Answer 1

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Answer 2

ANSWER:---------

Element in A¹,A²,A³..../A³0=4³0{×}5

{NOTE}each element is used 10 times.

So, S=30{×}5 divided by 10

hence proved ,answer =15

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